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A vessel of 120 mL capacity contains a certain amount of gas at temperature 35^(@)C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at temperature 35^(@)C, What would be its pressure ?

Answer» <html><body><p></p>Solution :When <a href="https://interviewquestions.tuteehub.com/tag/fixed-457597" style="font-weight:bold;" target="_blank" title="Click to know more about FIXED">FIXED</a> mass of any gas is <a href="https://interviewquestions.tuteehub.com/tag/poured-7256597" style="font-weight:bold;" target="_blank" title="Click to know more about POURED">POURED</a> to one container to another container then its pressure, volume and temperature is as under.<br/>Container - 1st : Initial volume `(V_(1))=120` <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a><br/>Initial pressure `(p_(1))=1.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` bar <br/>Temperature `(T) = 35^(@)C`<br/>Container - 2nd : Final volume `(V_(2))=180` mL<br/>Temperature (T) `= 35^(@)C`<br/>Final pressure `(p_(2))=(?)`<br/>Temperature is constant at `35^(@)C` and mass of gas is constant so according to Boyle.s <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a>.<br/>`p_(1)V_(1)=p_(2)V_(2)`<br/>`therefore p_(2)=(p_(1)V_(1))/(V_(2))=(("1.2 bar")xx(120 mL))/(180 mL)=0.8` bar<br/>Pressure of container - 2nd would be 0.8 bar.</body></html>


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