A vessel of 120 mL capacity contains a certain amount of gas at temperature 35^(@)C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at temperature 35^(@)C, What would be its pressure ?

A vessel of 120 mL capacity contains a certain amount of gas at temper

1.	A vessel of 120 mL capacity contains a certain amount of gas at temperature 35^(@)C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at temperature 35^(@)C, What would be its pressure ?
Answer» Solution :When FIXED mass of any gas is POURED to one container to another container then its pressure, volume and temperature is as under. Container - 1st : Initial volume `(V_(1))=120` ML Initial pressure `(p_(1))=1.2` bar Temperature `(T) = 35^(@)C` Container - 2nd : Final volume `(V_(2))=180` mL Temperature (T) `= 35^(@)C` Final pressure `(p_(2))=(?)` Temperature is constant at `35^(@)C` and mass of gas is constant so according to Boyle.s LAW. `p_(1)V_(1)=p_(2)V_(2)` `therefore p_(2)=(p_(1)V_(1))/(V_(2))=(("1.2 bar")xx(120 mL))/(180 mL)=0.8` bar Pressure of container - 2nd would be 0.8 bar.