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A vessel of irregular shape has a volume 'V'. It is first evacuated and coupled with a vessel of 4L capacity at 35^@C and 10 atm pressure. If the final pressure in both the vessels is 3atm, calculate the volume V.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/unknown-1438723" style="font-weight:bold;" target="_blank" title="Click to know more about UNKNOWN">UNKNOWN</a> vesselKnown vessel<br/> `V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = VL ""V_(2) = 4L` <br/> `P_(1) = 0 "atm" P_(2) = 10` atm <br/> The average pressure (P) of the mixture of the <a href="https://interviewquestions.tuteehub.com/tag/gases-13668" style="font-weight:bold;" target="_blank" title="Click to know more about GASES">GASES</a> from two vessels ` = P = (P_(1)V_(1)+ P_(2)V_(2))/(V_(1) + V_(2))` <br/> ` 3 = (0 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> V + 10 xx 4)/(V + 4) = (<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)/(V + 4)` <br/> Solving, V = 9.3 L <br/> The volume of the given vessel of irregular shape is 9.3 L</body></html>


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