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A vessel of irregular shape has a volume 'V'. It is first evacuated and coupled with a vessel of 4L capacity at 35^@C and 10 atm pressure. If the final pressure in both the vessels is 3atm, calculate the volume V. |
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Answer» Solution :UNKNOWN vesselKnown vessel `V_(1) = VL ""V_(2) = 4L` `P_(1) = 0 "atm" P_(2) = 10` atm The average pressure (P) of the mixture of the GASES from two vessels ` = P = (P_(1)V_(1)+ P_(2)V_(2))/(V_(1) + V_(2))` ` 3 = (0 XX V + 10 xx 4)/(V + 4) = (40)/(V + 4)` Solving, V = 9.3 L The volume of the given vessel of irregular shape is 9.3 L |
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