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A water fountain on the ground sprinkles water all around it. If the speed of the water coming out of the fountain is v. Calculate the total area around the fountain that gets wet.

Answer» <html><body><p><br/></p>Solution :Water comes from a fountain can be <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> as projectile and the distance covered is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> range of projectile i.e., `theta=45^(@)` <br/> `:.` Rang of the particle `(R_(max))=(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2))/(g)sin2theta=(v^(2))/(g)` <br/> here, `R_(max)` is radius of the area covered. <br/> `:.` area covered `pir^(2)=piR_(max)^(2)=<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>((v^(2))/(g))" Area" (piv^(2))/(g^2)`</body></html>


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