1.

A weak acid HX has K_(a) =1 xx 10^(-5)M. If forms a salt NaX onreaction with alkali. The perentage degree of dissociation of 0.1 M solution of NaX is

Answer»

1.0E-5
0.01
0.1
0.15

Solution :`underset(("Salt"))(X^(-)) +H_(2)O hArr HX+OH^(-)`
For the salt `K_(h) =(K_(w))/(K_(a)) =Calpha^(2)`
`:. (10^(-4))/(10^(-5)) =0.1 alpha^(2)`
`" or """alpha^(2) =(10^(-14))/(10^(-6)) =10^(-8)`
`alpha =(10^(-8))^(1//2) =10^(-4)`
`% " degree of DISSOCIATION "underset(=10^(-2) =0.01%)(=10^(-4) XX 100)`


Discussion

No Comment Found