1.

A weak acid HX has the dissociation constant 1xx10^(-5)M. It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX is

Answer»

`0.0001%`
`0.01%`
`0.1%`
`0.15%`

Solution :Hydrolysis reaction is `X^(-) + H_(2)O HARR HX+OH^(-)` For a salt of WEAK acid with STRONG base, `K_(h)=(K_(w))/(K_(a))=ch^(2)`
`:. (10^(-14))/(10^(-5))=0.1xxh^(2) or h^(2) = 10^(-8) or h = 10^(-4)`
% hydrolysis `= 10^(-4) xx 100 = 10^(-2) = 0.01`


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