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A weak acid HX has the dissociation constant 1xx10^(-5)M. It forms a salt NaX on reaction with alkali. The degree of hydrolysis of 0.1 M solution of NaX is

Answer» <html><body><p>`0.0001%`<br/>`0.01%`<br/>`0.1%`<br/>`0.15%`</p>Solution :Hydrolysis reaction is `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(-) + H_(2)O <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a> HX+OH^(-)` For a salt of <a href="https://interviewquestions.tuteehub.com/tag/weak-729638" style="font-weight:bold;" target="_blank" title="Click to know more about WEAK">WEAK</a> acid with <a href="https://interviewquestions.tuteehub.com/tag/strong-653928" style="font-weight:bold;" target="_blank" title="Click to know more about STRONG">STRONG</a> base, `K_(h)=(K_(w))/(K_(a))=ch^(2)` <br/> `:. (10^(-14))/(10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>))=0.1xxh^(2) or h^(2) = 10^(-8) or h = 10^(-4)` <br/> % hydrolysis `= 10^(-4) xx 100 = 10^(-2) = 0.01`</body></html>


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