A weak base BOH is tirated against 0.1 M of HCl solution. The following table indicates the volumes of HCl added and pH of solution. From this data the pK_b of base may be.

A weak base BOH is tirated against 0.1 M of HCl solution. The followin

1.	A weak base BOH is tirated against 0.1 M of HCl solution. The following table indicates the volumes of HCl added and pH of solution. From this data the pK_b of base may be.
Answer» <html><body><p>`4.74` <br/>` 4.3` <br/>` 4.<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a> ` <br/>` 4.5` </p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/poh-1145204" style="font-weight:bold;" target="_blank" title="Click to know more about POH">POH</a> =pK_b +log ""( S)/(B) ` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>- 10.04 = pK_b +log ""( 0.1 xx 5 )/(40 B -0.1 xx 5) ` <br/> ` rArr 3.96 =pK_b +log ""( 0.5 )/(40 B -0.5 )......(1) ` <br/>` 14- 9, 14 =pK_b +log"" ( 0.1 xx 20)/( 40 B -0.1 xx 20 ) ` <br/>`rArr 4.86 = pK_b +log ""( <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(40B - 2) ....(2) ` <br/>` 0.9 = log"" ( 2)/( 40 B-2) xx ( 40 B -0.5 )/( 0.5 ) ` <br/> ` 8 = 4xx ( 40 B-0.5)/( 40 B -2) rArr 80 B -4 =40 B -0.5` <br/> ` 40 B =3.5 rArr B =(3.5)/(40) ` <br/> substituting in (1) <br/> ` 4.86 =pKb+ log"" (2)/(3.5-2 )rArr pK_b =4.74`</body></html>