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A weak monobasic acid is 1% ionized in 0.1 M solution at 25^(@)C. The percentage ionization in its 0.025 M solution is

Answer»

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Solution :`HAhArrH^(+)+A^(-)`,
`K=Calpha^(2)=0.1xx((1)/(100))^(2)=10^(-5)`
When `C=0.025,alpha=sqrt((K)/(C))=sqrt((10^(-5))/(0*025))=0*02`
`:.%" ionization "=2%`.


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