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A weak monobasic acid is 1% ionized in 0.1 M solution at 25^(@)C. The percentage ionization in its 0.025 M solution is |
Answer» <html><body><p>1<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>3<br/>4</p>Solution :`HAhArrH^(+)+A^(-)`, <br/> `K=Calpha^(2)=0.1xx((1)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>))^(2)=10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)` <br/> When `C=0.025,alpha=sqrt((K)/(C))=sqrt((10^(-5))/(0*025))=0*02` <br/> `:.%" ionization "=2%`.</body></html> | |