A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to stop in 20 s. Then, the angular retardation will be

A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to s

1.	A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to stop in 20 s. Then, the angular retardation will be
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a> pi rads^(-2)`<br/>`(pi)/(200) rads^(-2)`<br/>`(11 pi)/(200) rads^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Angular <a href="https://interviewquestions.tuteehub.com/tag/retardation-1187717" style="font-weight:bold;" target="_blank" title="Click to know more about RETARDATION">RETARDATION</a>, `alpha=(omega_(0))/(t)""(because 0=omega_(0)-alphat)` <br/> `=(2pixx33//60)/(20)=(11pi)/(200) "rad s"^(-2)`.</body></html>