A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to stop in 20 s. Then, the angular retardation will be

A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to s

1.	A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to stop in 20 s. Then, the angular retardation will be
Answer» `PI RAD s^(-2)` `11 pi rads^(-2)` `(pi)/(200) rads^(-2)` `(11 pi)/(200) rads^(-2)` SOLUTION :Angular RETARDATION, `alpha=(omega_(0))/(t)""(because 0=omega_(0)-alphat)` `=(2pixx33//60)/(20)=(11pi)/(200) "rad s"^(-2)`.