A white crystalline substance dissolves in hot water. On passing H_(2)S in this solution, black precipitate is obtained. The black precipitate dissolves completely in hot HNO_(3). On adding a few drops of conc. H_(2)SO_(4), a white precipitate is obtained. this substance is :

A white crystalline substance dissolves in hot water. On passing H_(2)

1.	A white crystalline substance dissolves in hot water. On passing H_(2)S in this solution, black precipitate is obtained. The black precipitate dissolves completely in hot HNO_(3). On adding a few drops of conc. H_(2)SO_(4), a white precipitate is obtained. this substance is :
Answer» `BaSO_(4)` `SrSO_(4)` `PbCl_(2)` `CdSO_(4)` Solution :White ppt is of `PbCl_(2)`. It dissolves in hot water `PbCl_(2) + H_(2)S RARR underset(("Black ppt"))(PbS) + 2HCl` PbS dissolves in hot conc. `HNO_(3)` and gives white ppt on adding conc. `H_(2)SO_(4)`