A white crystalline substance dissolves in hot water. On passing H_(2)S in this solution, black precipitate is obtained. The black precipitate dissolves completely in hot HNO_(3). On adding a few drops of conc. H_(2)SO_(4), a white precipitate is obtained. this substance is :

A white crystalline substance dissolves in hot water. On passing H_(2)

1.	A white crystalline substance dissolves in hot water. On passing H_(2)S in this solution, black precipitate is obtained. The black precipitate dissolves completely in hot HNO_(3). On adding a few drops of conc. H_(2)SO_(4), a white precipitate is obtained. this substance is :
Answer» <html><body><p>`BaSO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`SrSO_(4)`<br/>`PbCl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`CdSO_(4)`</p>Solution :White ppt is of `PbCl_(2)`. It dissolves in hot water <br/> `PbCl_(2) + H_(2)S <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> underset(("Black ppt"))(PbS) + 2HCl` <br/> PbS dissolves in hot conc. `HNO_(3)` and gives white ppt on adding conc. `H_(2)SO_(4)`</body></html>