A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2), calculate the elongation produced in the wire. Take g = 10 ms^(-2)

A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It

1.	A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2), calculate the elongation produced in the wire. Take g = 10 ms^(-2)
Answer» <html><body><p></p>Solution :We know that`(F)/(A)=<a href="https://interviewquestions.tuteehub.com/tag/yxx-750220" style="font-weight:bold;" target="_blank" title="Click to know more about YXX">YXX</a>(DeltaL)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)` <br/> `DeltaL=(F/A)(L/Y)=((<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)/(1.25xx10^(-4)))((10)/(4xx10^(10)))=10^(-4)m`</body></html>