A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2), calculate the elongation produced in the wire. Take g = 10 ms^(-2)

A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It

1.	A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2), calculate the elongation produced in the wire. Take g = 10 ms^(-2)
Answer» Solution :We know that`(F)/(A)=YXX(DeltaL)/(L)` `DeltaL=(F/A)(L/Y)=((50)/(1.25xx10^(-4)))((10)/(4xx10^(10)))=10^(-4)m`