InterviewSolution
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A wire 88 cm long is bent into a circular loop and kept with its plane perpendicular to a magnetic field of induction 2.5 Wb/m2. Within 0.5 second, the coil is changed to a square and the magnetic induction is increased by 0.5 Wb/m2.. Calculate the emf induced in the wire. |
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Answer» Data: l = 88 cm, B = 2.5 Wb/m2, B = 3 Wb/m2, ∆t = 0.5 s For the circular loop, l = 2πr ∴ r = \(\cfrac{l}{2\pi}\) = \(\cfrac{88}{2\times(22/7)}\) = 14 cm = 0.14 m Area of the circular loop, Ai = πr2 = \(\cfrac{22}7\)(0.14)2 = 0.0616 m2 Initial magnetic flux, Φi = AiBi = 0.0616 × 2.5 = 0.154 Wb For the square loop, length of each side = \(\cfrac{88}4\) cm = 22 cm = 0.22 m4 Area of the square loop, Af = (0.22)2 = 0.0484 m2 ∴ Final magnetic flux, Φf = AfBf = 0.0484 × 3 = 0.1452 Wb Induced emf, e = – \(\cfrac{Φ_f−Φ_1}{Δt}\) = \(\cfrac{Φ_1−Φ_f}{Δt}\) ∴ e = \(\cfrac{0.154 - 0.1452}{0.5}\) =8.8 x 10-3 x 2 = 1.76 × 10-2 V |
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