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A wire of length L and radius r is clamped rigidly at one end. When the other end of the wire is pulled by a force f its length increases by l. Another wire of the same material of length 2L and radius 2r is pulled by a force 2f. Then find the increase in length of this wire. |
Answer» <html><body><p>`l/2`<br/>`l`<br/>`2l`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4l-318786" style="font-weight:bold;" target="_blank" title="Click to know more about 4L">4L</a>`</p>Solution :`Y = (<a href="https://interviewquestions.tuteehub.com/tag/fl-462549" style="font-weight:bold;" target="_blank" title="Click to know more about FL">FL</a> )/( Al) = (f L )/( pi <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ^(2)l )` <br/> `therefore l = ( fL )/( pi r ^(*2) Y)` <br/> Now for increase in <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> for second wire, <br/> `l . = ((2 f ) (2L ))/( pi (2r) ^(2) l )= (<a href="https://interviewquestions.tuteehub.com/tag/4f-318725" style="font-weight:bold;" target="_blank" title="Click to know more about 4F">4F</a> L )/( 4pi r ^(2) l )` <br/> `l .=l`</body></html> | |