InterviewSolution
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InterviewSolution
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(a) Write balanced equations for the following reactions : (i) Chlorine reacts with dry slacked lime. (ii) Carbon reacts with concentrated `H_2SO_4`. (b) Describe the contact process for the manufacture of sulphuric acid with special referecen to the reaction conditions, catalysts used and the yields in the process. |
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Answer» (a) (i) `2Cl_2+2Ca(OH)_2 to CaCl_2+Ca(OCL_2)+2H_2O` (ii) `C+2H_2SO_4to CO_2+2SO_22H_2O` (b) In the contact process the sulphur dioxide is mixed with air and the mixture passed over a catalyst of vanadium (v) oxide `V_2O_5` at a relatively high temperature of about `450^@C` and at a pressure of between 1-2 atm. it is an exothermic oxidation . `(1) 2SO_2(g)+O_2(g) hArr 2SO_3(g)" "(DeltaH=-196kJmol^(-))` `K_(P)=(PSO_(3)^(2))/(PSO_(2)^(2)PO_2)` (2) The sulphur trioxide is dissolved in concentrated sulphuric acid to form fuming sulphuric acid (oleum). `SO_((3)(g))+H_2SO_((4)(l)) hArrH_2SO_((4)(l))` (3) Water is then carefully added ot the oleum to produce concentrated sulphuric acid (`98%H_2SO_4`) `H_2S_2O_(7(l))+H_2O_(l)hArr2H_2SO_(4(l)` If the sulphur trioxide is added directly to water an acid mist from which is difficult to contain because the reaction to form sulphuric acid solution is very exothermic with a big K value. |
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