1.

A yellow turbidity, sometimes appears on passing H_(2)S gas ever in the absence of the second group radicals. This happens because

Answer»

SULPHUR is present in the mixture as an impurity
the fourth group radicals are precipitated as sulphides
`H_(2)S` is oxidised by some ACIDIC radical present in solution
the third group radicals are precipitated
Aqueous sodium hydroxide reacts with a METAL ion

Solution :`H_(2)S` oxidised by some acid radical (e.g. `NO_(3)^(-)` salt) present in the mixture is to sulphur which APPEARS as yellow turbidity


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