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A yellow turbidity, sometimes appears on passing H_(2)S gas ever in the absence of the second group radicals. This happens because

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/sulphur-1234343" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHUR">SULPHUR</a> is present in the mixture as an impurity<br/>the fourth group radicals are precipitated as sulphides<br/>`H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)S` is oxidised by some <a href="https://interviewquestions.tuteehub.com/tag/acidic-847601" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDIC">ACIDIC</a> radical present in solution<br/>the third group radicals are precipitated <br/> Aqueous sodium hydroxide reacts with a <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> ion</p>Solution :`H_(2)S` oxidised by some acid radical (e.g. `NO_(3)^(-)` salt) present in the mixture is to sulphur which <a href="https://interviewquestions.tuteehub.com/tag/appears-881937" style="font-weight:bold;" target="_blank" title="Click to know more about APPEARS">APPEARS</a> as yellow turbidity</body></html>


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