A5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K

A5% solution (by mass) of cane sugar in water has freezing point of 27

1.	A5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K
Answer» <html><body><p></p>Solution :Molar <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of cane sugar <br/> `C_(12) H _(22) O _(11) = 342 g <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> ^(-1)` <br/> Molality of sugar `= (<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> xx 100)/( 342 xx 100) = 0.146` <br/> `Delta T_(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)` for sugar solution `=273.15 - 271=2.15^(@)` <br/> `Delta T_(f) = K_(f) xxm` <br/> `K _(f) = (2.15)/(0.146)` <br/> Molality of glucose solution `= (5)/(180) xx (1000)/(100) = 0.278 =4.09^(@)K` <br/> `therefore` Freezing point of glucose solution `=273.15-4.09 =269.06K`</body></html>