A5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K

A5% solution (by mass) of cane sugar in water has freezing point of 27

1.	A5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculatge the freezing point of 5% glucose in water if freezing point of pure water is 273.15K
Answer» Solution :Molar MASS of cane sugar `C_(12) H _(22) O _(11) = 342 g MOL ^(-1)` Molality of sugar `= (5 xx 100)/( 342 xx 100) = 0.146` `Delta T_(F)` for sugar solution `=273.15 - 271=2.15^(@)` `Delta T_(f) = K_(f) xxm` `K _(f) = (2.15)/(0.146)` Molality of glucose solution `= (5)/(180) xx (1000)/(100) = 0.278 =4.09^(@)K` `therefore` Freezing point of glucose solution `=273.15-4.09 =269.06K`