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AB_(2) " dissociates as " : AB_(2) (g) hArr AB (g) + B (g). If the intial pressure is 500 mm of Hg and the total pressure at equilibriumis 700 mm 0f Hg, calculate K_(p)for the reaction.

Answer» <html><body><p></p>Solution :After dissociation , suppose the decrease in the pressure of `AB_(2)` at equilibrium is p <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a>. Then <br/> ` {:(,AB_(2) (<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>),hArr,AB (g),+,B (g)),(" Intial pressure",500 mm,,0,,0),(" Pressures at eqm.",(500-)p " mm", ,p" mm",,p " mm"):} ` <br/> `:. " Total pressure at equilibrium " = 500 - p + p+ p = 500 + p" mm"` <br/> `500 + p = 700" (Given) " or p= 200 " mm"` <br/> Hence , at equilibrium `p _(AB_(2)) = 500 - 200 = 300 " mm" , 200 " mm ", p_(B) = 200 mm ` <br/> `:. K_(p) = (p_(AB) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> p_(B))/p_(AB_(2)) = (200 xx 200)/300 = 133*<a href="https://interviewquestions.tuteehub.com/tag/3mm-311030" style="font-weight:bold;" target="_blank" title="Click to know more about 3MM">3MM</a>` <br/> Note. With <a href="https://interviewquestions.tuteehub.com/tag/respect-1186739" style="font-weight:bold;" target="_blank" title="Click to know more about RESPECT">RESPECT</a> to standard state pressure of 1 bar , i.e., 0*987 atm , i.e., 750 mm, `K_(p) = (133*3)/750=0*178.`</body></html>


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