AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then

AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial

1.	AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then
Answer» <html><body><p>`alpha = 33.3%`<br/>`K_p = 100mm`<br/>equilibrium pressure of `AB_2` is 400mm<br/>equilibrium pressure of <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is 200mm</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AO_CHE_XI_V01_B_C04_E01_065_S01.png" width="80%"/> <br/> `P_(<a href="https://interviewquestions.tuteehub.com/tag/eqn-973463" style="font-weight:bold;" target="_blank" title="Click to know more about EQN">EQN</a>)=<a href="https://interviewquestions.tuteehub.com/tag/600-329515" style="font-weight:bold;" target="_blank" title="Click to know more about 600">600</a>+P=800 implies P=<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> prop (200)/(600)=1//3`</body></html>