AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then

AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial

1.	AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)). The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then
Answer» `alpha = 33.3%` `K_p = 100mm` equilibrium pressure of `AB_2` is 400mm equilibrium pressure of B is 200mm Solution : `P_(EQN)=600+P=800 implies P=200 prop (200)/(600)=1//3`