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AB , A_(2) and B_(2) are diatomic molecules, if the bond enthalpies of A_(2) , AB and B_(2) are in the ratio of 1:1:0.5 and the enthaly of formation of AB from A_(2) gives AO and DeltaH_(c)=-1200KJ mol^(-1) . Bond energy of (O=O) bond is 500KJ mol^(-1) . What is the bond enthalpy of (A-O) bond ?

Answer» <html><body><p>`400KJmol-1` <br/>`1650KJmol-1` <br/>`1200KJmol-1` <br/>`200KJmol-1` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Bond enthalpy `(BE)` of `A_(2)=x,AB=x` and `B_(2)=(x)/(2)` <br/> `(1)/(2)A_(2)+(1)/(2)B_(2)rarrAB-100KJ//mol^(-1)` ...(i) <br/> `(1)/(2)A_(2)+(1)/(2)O_(2)rarrAO-1200KJ//mol` (given) <br/> `A_(2)+O_(2)rarr2AO-2400KJ//mol` ...(ii) <br/> `O=Orarr500KJ//mol` <br/> From eq. (i) <br/> `(1)/(2)B.E._(A_(2))+(1)/(2)B.E._(B_(2))-B.E._(AB)=-100` <br/> `(1)/(2)x+(x)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)-x=-100` <br/> `-(x)/(4)=-100` <br/> `x=400(kJ)/(mol)` <br/> Now from eq (ii) <br/> `B.E._(A_2)+B.E._(O_2)-2B.E._(AO)=-<a href="https://interviewquestions.tuteehub.com/tag/2400-296074" style="font-weight:bold;" target="_blank" title="Click to know more about 2400">2400</a>` <br/> `x+(+500)-2B.E._(AO)=-2400` <br/> `400+500-2B.E._(AO)=-2400` <br/> `-B.E._(AO)=-3300` <br/> `B.E._(A-O)=<a href="https://interviewquestions.tuteehub.com/tag/1650-277626" style="font-weight:bold;" target="_blank" title="Click to know more about 1650">1650</a>(kJ)//(mol)`</body></html>


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