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AB ADy in Fig. 6. 19, DE 11 AC and DF IAE. Prove thatBF BEFE ECFig. 6.19 |
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Answer» BASIC PROPORTIONALITY THEOREM (BPT) : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio. That is also known as Thales theorem.SOLUTION: GIVEN:In ∆BAC, DE || ACBE/EC = BD/DA………..(1) [ By Thales theorem(BPT)] In ∆BAE, DF || AE (GIVEN)BF/FE = BD/DA………..(2) [ By Thales theorem(BPT)] (From eq 1 and 2)BF/FE = BE/ECFE/BF = EC/BE [reciprocal the terms] Hence proved. |
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