1.

According to Boyle's law

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`(dP//dV)_(T) = K//V^(2)`
`(dP//dV)_(T) = - K//V`
`(dV//dP)_(T) = - K//P^(2)`
`(dV//dP)_(T) = - K//P`

Solution :According to BOYLE's law at constant temperature
`V prop 1/P""`or `""V=K/P`
`:. (dV//dP)_(T)= -K//P^(2)`
`P=K/V`


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