InterviewSolution
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InterviewSolution
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According to Kohlrausch law, the limiting molar conductivity of an electrolyte, `A_(m)B_(n)`, can be expressed asA. `Lambda_(m)^(0)=m_(+)lambda_(A^(n+))^(0)-n_lambda_(B^(m-))^(0)`B. `Lambda_(m)^(0)=m_(+)lambda_(A^(m+))^(0)+n_lambda_(B^(n-))^(0)`C. `Lambda_(m)^(0)=n_(+)lambda_(A^(m+))^(0)-m_lambda_(B^(n-))^(0)`D. `Lambda_(m)^(0)=m_(+)lambda_(A^(n+))^(0)-n_lambda_(B^(m-))^(0)` |
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Answer» Correct Answer - D On the basis of conductivity measurements on a series of strong electrolytes, Kohlrausch discovered that this moalr conductivity at infinite dilutionis the sum of the contributions from each ion. It is thus knowm as the law of independent mifration (or mobility) of ions. Here `m_(+)` and `n_(-)` are numbers of cations and anions per formula unit, respectively and `lambda_(A^(n+))^(0)` and `lambda_(B^(m-))^(0)` are the corresponding molar conductivities of the ions at infinite dilution. |
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