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| 1. |
According to molecular orbital theory |
| Answer» <html><body><p>`C_(2)^(2-)` is expected to be diamgnetic <br/>`O_(2)^(2+)` is expected to have a longer bond length then `O_(2)` <br/>`N_(2)^(+) and N_(2)^(-)` have the same <a href="https://interviewquestions.tuteehub.com/tag/order-1138220" style="font-weight:bold;" target="_blank" title="Click to know more about ORDER">ORDER</a> <br/>`He_(2)^(+)` has the same energy as <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> isolated. He atoms </p>Solution :In `C_(2)^(2-)` , total number of electrons = 14 (even) <br/> Hence , it is diamagnetic<br/>`O_(2)^(2+)` has bond order = 3 ,`O_(2)` has bond order <br/> = 2.5 . Hence , bond length in `O_(2)^(2+)` is <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> than<br/> that in `O_(2)` . <br/> Bond order of `N_(2)^(+)` = Bond order of `N_(2)^(-) = 2.5` <br/> Bond order of `He_(2)^(+) = (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)` ,i.e., it exists . Hence , <br/> some energy is relesed when `He_(2)^(+)` is formed from<br/> two isolated He atoms.</body></html> | |