1.

According to molecular orbital theory

Answer»

`C_(2)^(2-)` is expected to be diamgnetic
`O_(2)^(2+)` is expected to have a longer bond length then `O_(2)`
`N_(2)^(+) and N_(2)^(-)` have the same ORDER
`He_(2)^(+)` has the same energy as TWO isolated. He atoms

Solution :In `C_(2)^(2-)` , total number of electrons = 14 (even)
Hence , it is diamagnetic
`O_(2)^(2+)` has bond order = 3 ,`O_(2)` has bond order
= 2.5 . Hence , bond length in `O_(2)^(2+)` is LESS than
that in `O_(2)` .
Bond order of `N_(2)^(+)` = Bond order of `N_(2)^(-) = 2.5`
Bond order of `He_(2)^(+) = (1)/(2)` ,i.e., it exists . Hence ,
some energy is relesed when `He_(2)^(+)` is formed from
two isolated He atoms.


Discussion

No Comment Found