1.

According to molecular orbital theory, which of the following will not be a viable molecule ?

Answer»

`He_(2)^(2-)`
`He_(2)^(+)`
`H_(2)^(-)`
`H_(2)^(2-)`

SOLUTION :Both `H_(2)^(2+) (2e^(-)) : SIGMA 1 s^(2) , B.O. 2//2=1`
` H_(2)^(2+) (3e^(-)):sigma 1 s^(2) sigma^(**) 1 s^(1) , B.O. = (2-1)/(2) = 0.5`
`H_(2)^(-) (3e^(-)): sigma 1 s^(2) sigma^(**)1 s^(1) , B.O. = (2-1)/(2) = 5.0`
`H_(2)^(2-) (4e^(-)): sigma 1 s^(2) sigma^(**)1 s^(2) , B.O. = (2-2)/(2) = 0`
THUS , `H_(2)^(2-)` connot exist as it has zero BOND order


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