According to the Bohr Theory, the third from the red end corresponds to which one of the following transitions in the hydrogen atom will give rise to the least energetic photon ?

According to the Bohr Theory, the third from the red end corresponds t

1.	According to the Bohr Theory, the third from the red end corresponds to which one of the following transitions in the hydrogen atom will give rise to the least energetic photon ?
Answer» N = 6 to n = 1 n = 5 to n = 4 n = 6 to n = 5 n = 5 to n = 3 Solution :`Delta E = 13.6 ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2) eV` `(1)/(1^(2)) - (1)/(6^(2)) = 1 - (1)/(36) = (35)/(36), (1)/(4^(2)) - (1)/(5^(2)) = (1)/(16) - (1)/(25) = (9)/(400)` `(1)/(5^(2)) - (1)/(6^(2)) = (1)/(25) - (1)/(36) = (11)/(36 xx 25)` `(1)/(3^(2)) - (1)/(5^(2)) = (1)/(9) - (1)/(25) =(16)/(225)` Thus `Delta E` will be MINIMUM for the TRANSITION n = 6 to n = 5