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Accound for the following with ittle or no PhCH_(2)(Br)CH_(3))_(2) formed. |
Answer» Solution : This REACTION proceeds VIA free radical mechanism forming 2 free RADICALS, of which `2^(@)` benzylic free radical is stabilized more by resonance of phenyl ring and with HYPERCONJUGATION of `-CH_(3)` group, thus resulting in the formation of `PhCH(Br)CH(CH_(3))_(2)` as the major product. |
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