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Accound for the following with ittle or no PhCH_(2)(Br)CH_(3))_(2) formed.

Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_261_S01.png" width="80%"/> <br/> This <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> proceeds <a href="https://interviewquestions.tuteehub.com/tag/via-723599" style="font-weight:bold;" target="_blank" title="Click to know more about VIA">VIA</a> free radical mechanism forming <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> free <a href="https://interviewquestions.tuteehub.com/tag/radicals-1175948" style="font-weight:bold;" target="_blank" title="Click to know more about RADICALS">RADICALS</a>, of which `2^(@)` benzylic free radical is stabilized more by resonance of phenyl ring and with <a href="https://interviewquestions.tuteehub.com/tag/hyperconjugation-13962" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERCONJUGATION">HYPERCONJUGATION</a> of `-CH_(3)` group, thus resulting in the formation of `PhCH(Br)CH(CH_(3))_(2)` as the major product.</body></html>


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