InterviewSolution
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InterviewSolution
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Account for the following (i) Reducing character decreases from `SO_(2)` to `TeO_(2).` (ii) `HClO_(3)` is a stronger acid than HClO. (iii) Xenon forms compounds with fluorine and ozygen only. (b) Complete the following equations : (i) `4NaCl+MnO_(2)+4H_(2)SO_(4)to` (ii) `6XeF_(4)+12H_(2)Oto` |
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Answer» (a) (i) Since +6 oxidiation state of S is more stable than +4, therefore, `SO_(2)` act as a reducing agent. Since the stability of +6 oxidatin decreases from S to Te, therfore, reducing character decreases from `SO_(2)` to `TeI_(2).` (ii) `overset(+5)(HClO_(3)),overset(+1)(HClO)` Greater the number of oxygen atoms in anion (formed by the removal of Hydrogen ) greater will be the dispersal of negative charge through p `pi-d pi` back bonding and hence greater will be the stability of anions, greater will be the acidity. Hence `HClO_(3)` is stronger acid than HClO. (iii) Fluorine and oxygen are the most electronegative elements and hence are very reactive. Therefore, Xenon forms compounds with flurine and oxygen only. (b) (i) `4NaCl+MnO_(2)+4H_(2)SO_(4)to MnCl_(2)+4NaHSO_(4)+2H_(2)O+Cl_(2)` (ii) `6XeF_(4)+12H_(2)O to4Xe+2XeO_(3)+24HF+3O_(2)` |
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