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Acetic acid is added to the solution of sodium carbonate the gas evolved does not turn purple colour of KMnO_(4) but turns lime water milky forming a compound (M) which becomes soluble by passing the same gas in excess forming another compound (N). But same obserbation is not obtained with boric acid. The compound formed in the above sequence (M) and (N) are respectively.

Answer» <html><body><p>water <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> `CaCO_(3)` and water soluble `Ca(HCO_(3))_(2)`<br/>water insoluble `CaCO_(3)` and water insoluble `Ca(HCO_(3))_(2)`<br/>water insoluble `CaCO_(3)` and water soluble `Ca(HCO_(3))_(2)`<br/>water soluble `CaCO_(3)` and water insoluble `Ca(HCO_(3))_(2)`</p>Solution :`Na_(2)CO_(3) overset(<a href="https://interviewquestions.tuteehub.com/tag/acoh-1966500" style="font-weight:bold;" target="_blank" title="Click to know more about ACOH">ACOH</a>)rarr CO_(2) overset(Ca(OH)_(2))rarr underset((M))(CaCO_(3)<a href="https://interviewquestions.tuteehub.com/tag/darr-943899" style="font-weight:bold;" target="_blank" title="Click to know more about DARR">DARR</a>) overset(CO_(2))underset(H_(2)O)rarr underset((N))(Ca(HCO_(3))_(2))`</body></html>


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