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Acic base + Redox titration 1^(st)titration : M/10 reacts with oxalic acid as well as H_(2)SO_4according to equation H_(2)C_(2)O_4 + NaOH rarrNa_(2)C_(2)O_4 + H_(2)O, H_(2)SO_(4)) + NaOH rarr Na_(2)SO_(4) + H_(2)O 2^(nd)titration : The mixture solution is titrated with M/10KMnO_4 solution which will reacts with oxalic acid (redox titration) in the presence of H_(2)SO_(4) H_(2)C_(2)O_(4) + underset(("Purple"))(KMnO_4)+H_(2)SO_(4) rarr K_(2)SO_(4) +underset(("Colourless"))( MnSO_4)+H_2O+CO_2 The reactionof oxalic acid with KMnO_4is very slow therefore the oxalic acid solution is heated to 60-70^@Cinitially. Once the reation has started, its rate automatically increases. MnO_4^(-)acts as an oxidising agent. MnO_(4)^(-)overset(H^(+))rarrunderset("colourless")(Mn^(++),MnO_(4)^(--),MnO_(4) underset(H_2O)rarroverset("Brown ppt")(MnO_2)Which statement is wrong?

Answer» <html><body><p> In NaOH titration phenolphthalein indicator will be suitable <br/> In redox titration with `KMnO_4`the `KMnO_4`itself acts as self indicator <br/> <a href="https://interviewquestions.tuteehub.com/tag/sulphuric-655420" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHURIC">SULPHURIC</a> acid should be added in <a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a> other wise brown ppt of `MnO_2`may appear<br/>Both `H_2SO_4 and H_(2)C_(2)O_4`, are titrated with `KMnO_4`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Both `H_2 SO_4 and H_2C_2O_4`are titration with `KMnO_4`</body></html>


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