1.

Acidified Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added it this is due to the formation of

Answer»

`Cr_(2)(SO_(4))_(3)`
`CrO_(4)^(2-)`
`Cr_(2)(SO_(3))_(3)`
`CrSO_(4)`

Solution :`K_(2)Cr_(2)O_(7)//H_(2)SO_(54)` xoddieses `Na_(2)SO_(3)` to `Na_(2)SO_(54)` and itself gets reduced to `Cr_(2)(SO_(4)^(3))`


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