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Acidified Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added it this is due to the formation of

Answer» <html><body><p>`Cr_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))_(3)`<br/>`CrO_(4)^(2-)`<br/>`Cr_(2)(SO_(3))_(3)`<br/>`CrSO_(4)`</p>Solution :`K_(2)Cr_(2)O_(7)//H_(2)SO_(<a href="https://interviewquestions.tuteehub.com/tag/54-324973" style="font-weight:bold;" target="_blank" title="Click to know more about 54">54</a>)` xoddieses `Na_(2)SO_(3)` to `Na_(2)SO_(54)` and itself gets reduced to `Cr_(2)(SO_(4)^(3))`</body></html>


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