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Addition of HBr to 2-butene gives two products while that of HBr to 1-buane gives three products . Explain why ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Addition of HBr to 2-butene gives 2-bromobutane which being a chiral molecule <a href="https://interviewquestions.tuteehub.com/tag/exists-979838" style="font-weight:bold;" target="_blank" title="Click to know more about EXISTS">EXISTS</a> as two <a href="https://interviewquestions.tuteehub.com/tag/stereoisomers-13555" style="font-weight:bold;" target="_blank" title="Click to know more about STEREOISOMERS">STEREOISOMERS</a> ( I and II) .&lt;<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>&gt; <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E18_008_S01.png" width="80%"/> <br/> In contrast, 1-butene is an unsymmetrical molecule, therefore , it gives two products, i.e., 2-bromobutane (major product ) and 1-bromobutane (minor product). Since 2-bromobutane is a chiral molecule, it exists as two stereoisomers (I+II) as shown below above . While 1-bromobutane being a achiral molecule exists as such (III). <br/> `underset"1-Butene"(CH_3-CH_2-CH=CH_2) overset"HBr"to underset"I+II"(CH_3-CH_2-undersetunderset(Br)|overset**CH-CH_3)+underset"III"(CH_3CH_2CH_2CH_2-Br)` <br/> Thus, in all three products (I, II and III ) are <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a>.</body></html>


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