InterviewSolution
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InterviewSolution
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Addition of `HI` on the double bond of propene yield isopropyl iodide and not `n-` propyl iodide as the major product. This is because the addition proceeds throughA. A more stable free radicalB. A more stable carbanionC. A more stable carbonium ionD. None of the above being a concerted reaction |
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Answer» Correct Answer - c `HI rarr H^(+)+I^(-)` `CH_(3)-CH=CH_(2) + H^(+) to CH_(3) - underset({:(("Minor")),(1^(@)"Carboniumion"),(("Less stable")):})(CH_(2))-overset(+)(C )H_(2)+ CH_(3) +underset({:(("Minor")),(2^(@)"Carboniumion"),(("More stable")):})(overset(+)(C)H - CH_(3))` `CH_(3) underset(2^(@)"Carboniumion")(-overset(+)(C)H-CH_(3)) + I^(-) to underset({:("Isopropyl iodide"),("Major produce"):})underset(I)underset(|)(CH_(3)-CH)-CH_(3)` |
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