$ Addition of `NH_(4)OH` to an aqueous solution of `BaCl_(2)` in the presence of `NH_(4)Cl` (excess) precipitates `Ba(OH)_(2)`. ! `Ba(OH)_(2)` is insoluble in water.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true.

$ Addition of `NH_(4)OH` to an aqueous solution of `BaCl_(2)` in the p

1.	$ Addition of `NH_(4)OH` to an aqueous solution of `BaCl_(2)` in the presence of `NH_(4)Cl` (excess) precipitates `Ba(OH)_(2)`. ! `Ba(OH)_(2)` is insoluble in water.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true.
Answer» Addition of `NH_(4)OH` to an aqueous solution of `BaCl_2` in the presence `NH_(4)Cl` (excess) does not give a precipitate of `Ba(OH)_(2)` as `Ba(OH)_2` is soluble in water.

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