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Ag Br_(s) + 2S_2O_(3(aq) ) ^(2-) hArr Ag (S_2O_3)_(2(aq) ) ^(3-)+Br_(aq) ^(-)[Using :K_(sp)(AgBr)= 5xx 10 ^(-13)K_(f) (Ag(S_2O_3) _2^(3-) ) =5xx 10^(13) ] What is the molar solubility of AgBr in 0.1 M Na_2S_2O_3 |
Answer» <html><body><p>` 0.5 M` <br/>` 0.45 M` <br/>` 0.045 M` <br/>None of these </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Due to <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> `K_f,`<a href="https://interviewquestions.tuteehub.com/tag/almost-373246" style="font-weight:bold;" target="_blank" title="Click to know more about ALMOST">ALMOST</a> `Ag^(+) ` converts in to complex <br/>` {:(AgBr +2S_2 O_3^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a>, [Ag(S_2O_3)_2]^(3-) ,+Br) ,(0.1M,0,0),((0.1-2x),x,x):}` <br/>` 25= (x^(2))/((0.1-2x) ^(2) ), (x)/(0.1 - 2x) =5rArr x =0.045 M`</body></html> | |