AgBr_((s)) + 2S_(2)O_(3(aq))^(2-) hArr [Ag(S_(2)O_(3))_(2)]_((aq))^(3-) + Br_((aq))^(-) [Ksp(AgBr)= 5 xx 10^(-13), K_(f) [Ag(S_(2)O_(3))_(2)]^(3-) = 5 xx 10^(13)] What is the molar solubility of AgBr in 0.1 M Na_(2)S_(2)O_(3)?

AgBr_((s)) + 2S_(2)O_(3(aq))^(2-) hArr [Ag(S_(2)O_(3))_(2)]_((aq))^(3-

1.	AgBr_((s)) + 2S_(2)O_(3(aq))^(2-) hArr [Ag(S_(2)O_(3))_(2)]_((aq))^(3-) + Br_((aq))^(-) [Ksp(AgBr)= 5 xx 10^(-13), K_(f) [Ag(S_(2)O_(3))_(2)]^(3-) = 5 xx 10^(13)] What is the molar solubility of AgBr in 0.1 M Na_(2)S_(2)O_(3)?
Answer» <html><body><p>`0.5 M`<br/>`0.45 M`<br/>`0.045 M`<br/>`0.65 M`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Ag_((aq))^(+) + 2S_(2)O_(3(aq))^(2-)hArr[<a href="https://interviewquestions.tuteehub.com/tag/ag-362275" style="font-weight:bold;" target="_blank" title="Click to know more about AG">AG</a>(S_(2)O_(3))_(2)]_((aq))^(3-)` <br/> `AgBr_((s)) hArr Ag_((aq))^(+) + Br_(aq)^(-)` <br/> `ArBr_((s)) + <a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>((0.1-2x))(2S_(2)O_(3(aq))^(2-))hArr[Ag(S_(2)O_(3))_(2)]_((aq))^(3-)+Br_((aq))^(-)` <br/> `Ksp xx K_(f) = 25` <br/> As value of `K_(f)` is very higher so we can assume almost `Ag^(+)` inverts into complex <br/> `25 = (x^(2))/((0.1 - 2x)^(2)), 5 = (x)/(0.1-2x), x = 0.045 M`</body></html>