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Air contains N_(2) and O_(2) in the ratio of 4:1 by volume. The average conditions of temperature and pressure ?

Answer» <html><body><p>`12.0`<br/>`14.4`<br/>`15.6`<br/>`28.8`</p>Solution :As under similar conditions of <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> and pressure, equal volumes contain equal number of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> , therefore, molar ratio of `N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=4//5=0.8` and mol fraction of `O_(2)=0.2` <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/vapour-1442886" style="font-weight:bold;" target="_blank" title="Click to know more about VAPOUR">VAPOUR</a> density of air `=(28.8)/(2)=14.4`</body></html>


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