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AlF_(3) soluble in HF only in presence of KF. It is due to the formation of

Answer» <html><body><p>`K_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)[AlF_(3)H_(3)]`<br/>`K_(3)[AlF_(6)]`<br/>`AlH_(3)`<br/>`Kl[AlF_(3)H]`</p>Solution :Anhydrous`HF` is a covalentcompoundand is stronglyH-bounded . <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, it does not give `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>^(-)`ions andhence `AlF_(3)`does notcompoundcontains `F^(-)` ions. Therefore, it combineswith `AlF_(3)` to form <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> <a href="https://interviewquestions.tuteehub.com/tag/complex-926309" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLEX">COMPLEX</a>, `K_(3)[AlF_(6)]` <br/> `AlF_(3) + 3KF rarr K_(3)[AlF_(6)]`</body></html>


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