1.

AlF_(3) soluble in HF only in presence of KF. It is due to the formation of

Answer»

`K_(3)[AlF_(3)H_(3)]`
`K_(3)[AlF_(6)]`
`AlH_(3)`
`Kl[AlF_(3)H]`

Solution :Anhydrous`HF` is a covalentcompoundand is stronglyH-bounded . THEREFORE, it does not give `F^(-)`ions andhence `AlF_(3)`does notcompoundcontains `F^(-)` ions. Therefore, it combineswith `AlF_(3)` to form SOLUBLE COMPLEX, `K_(3)[AlF_(6)]`
`AlF_(3) + 3KF rarr K_(3)[AlF_(6)]`


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