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Alkane (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted into another alkane containing less than four carbon atoms. (A) is

Answer» <html><body><p></p>Solution :(i)Let A beR-H, on <a href="https://interviewquestions.tuteehub.com/tag/bromination-904631" style="font-weight:bold;" target="_blank" title="Click to know more about BROMINATION">BROMINATION</a> , it will give R-Br <br/> `underset"Alkane (A)" (R-H)+ Br_2 overset"hv"to underset"Alkyl bromide"(R-Br)+<a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a> ` <br/> (ii)Now Wurtz reaction of alkyl bromide gives alkane (B) <br/> `R-Br + 2Na + Br-R overset"Heat"to underset"Alkane (B)"(R-R) + 2NaBr` <br/> (iii)<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> alkane (B) contains less than four carbon atoms, therefore , R can have only one carbon atom. In other words , R is `CH_3` and hence alkane (A) is `CH_4` <br/> All the reactions <a href="https://interviewquestions.tuteehub.com/tag/involved-7257329" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVED">INVOLVED</a> here are : <br/> `underset"Methane (A)"(CH_4)underset"-HBr"overset(Br_2)to underset"Methyl bromide "(CH_3Br) underset"(Wurtz reaction)"overset"Na, Dry ether"to underset"(Less than 4 carbon atoms )"(CH_3-CH_3)`</body></html>


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