Alkane (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted into another alkane containing less than four carbon atoms. (A) is

Alkane (A) reacts with bromine by substitution to form an alkyl bromid

1.	Alkane (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted into another alkane containing less than four carbon atoms. (A) is
Answer» Solution :(i)Let A beR-H, on BROMINATION , it will give R-Br `underset"Alkane (A)" (R-H)+ Br_2 overset"hv"to underset"Alkyl bromide"(R-Br)+HBR ` (ii)Now Wurtz reaction of alkyl bromide gives alkane (B) `R-Br + 2Na + Br-R overset"Heat"to underset"Alkane (B)"(R-R) + 2NaBr` (iii)SINCE alkane (B) contains less than four carbon atoms, therefore , R can have only one carbon atom. In other words , R is `CH_3` and hence alkane (A) is `CH_4` All the reactions INVOLVED here are : `underset"Methane (A)"(CH_4)underset"-HBr"overset(Br_2)to underset"Methyl bromide "(CH_3Br) underset"(Wurtz reaction)"overset"Na, Dry ether"to underset"(Less than 4 carbon atoms )"(CH_3-CH_3)`