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"Alkane compound resist the oxidation", so what is your opinion for the following reaction ? C_(4)H_(10(g)) + (13)/(2)O_(2(g)) rarr 4CO_(2(g)) + 5H_(2)O_((l)) |
Answer» <html><body><p></p>Solution :The given <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> is of combustion of butane. Combustion is also an oxidation reaction, so in this reaction also oxidation occur. <br/> The negativity of C (2.5) and H (2.1) in reactant `C_(4)H_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)`, so negativity of carbon is more and so it possess negativestate, while in product `CO_(2)`, carbon possess +4 oxidation state. So in this reaction oxidation number of carbon <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> and so this reaction is of oxidation. "Combustion of all alkane is ultimately oxidation reaction only".</body></html> | |