InterviewSolution
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InterviewSolution
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Alkynes `(A)` and `(B)` hav ethe molecular formula `C_(8)H_(14)` giving following reactions: (A) or (B) `overset(H_(2)//Pt)rarr "n-Octane"`. `(A) overset(O_(3)//H_(2)O)rarr CH_(3)CH_(2)CH_(2)CO_(2)H` (B) `overset(Ag(NH_(3))_(2)OH)rarr` silver containing white ppt. Write the structure of `(A)` and `(B)`. |
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Answer» Correct Answer - N//A Since `(A)` and `(B)` by reduction using `H_(2)//Pt` gives `n`-Octane, hence both have straight chain `A overset(O_(3)//H_(2)O)rarr CH_(3)CH_(2)CH_(2)CO_(2)H` ("and no other compound") Hence, there should be two mole of this acid. Thus `A` is `CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)` `B` gives white ppt. containing `Ag` hence, `B` is terminal alkyne. Structure of `B` is `CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)C-=CH` |
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