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All the energy released from the reaction `XrarrY,Delta_(r)G^(@)=-193kJ"mol"^(-1)` is used for oxidising `M^(@)` as `M^(+)rarrM^(3+)+2e^(-),E^(@)=-0.25V`. Under standard conditions, the number of moles of `M^(+)`oxidised when one mole of X is converted to Y is `[F=96500C "mol"^(-1)]` |
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Answer» Given data is : `X to Y , Delta_(r)G^(@)=-193" kJ "mol^(-1)` `M^(+) to M^(3+)+2e^(-) , E^(@)=-0.25" V"` `193" kJ"` of energy is used to oxidise x mol of `M^(+)` ions to `M^(3+)` ions. For 1 mole of `M^(+)` `DeltaG^(@)=-nFE^(@)=(- mol)xx96500" C")xx(0.25" V")` `=48250" J "mol ^(-1)=48.25" kJ "mol^(-1)` `48.25" kJ"` of energy is used oxidise =1 mol 193.0 kJ of energy is used to oxidise `=(1 mol)xx((193.0" kJ"))/((48.25" kJ"))=4 mol " ":. x=4` |
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