InterviewSolution
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All the transformation took place without shedding a drop of blood or firing a single shot therefore, is know as Glorious or __________ * |
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Answer» Answer: FACTORIES form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 =(9x+5y+19)(9x+5y+19) Step-by-step explanation: GIVEN : Expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2
To find : Factories the expression? Solution : The given expression 81(x+1)^2+90(x+1)(y+2)+25(y+2)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 is in the form of a^2+2ab+b^2a 2 +2ab+b 2 in which a=9(x+1)a=9(x+1) b=5(y+2)b=5(y+2) We know, a^2+2ab+b^2=(a+b)^2a 2 +2ab+b 2 =(a+b) 2
Substitute a and b, (9(x+1))^2+2(9(x+1))(5(y+2))+(5(y+2))^2=((9(x+1))+(5(y+2)))^2(9(x+1)) 2 +2(9(x+1))(5(y+2))+(5(y+2)) 2 =((9(x+1))+(5(y+2))) 2
81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+9+5y+10)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 =(9x+9+5y+10) 2
81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)^281(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 =(9x+5y+19) 2
81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 =(9x+5y+19)(9x+5y+19) THEREFORE, factories form of the expression is 81(x+1)^2+90(x+1)(y+2)+25(y+2)^2=(9x+5y+19)(9x+5y+19)81(x+1) 2 +90(x+1)(y+2)+25(y+2) 2 =(9x+5y+19)(9x+5y+19) |
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