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Although both CO_(2) and H_(2)O are triatomic molecular , the shape of H_(2)O molecule is bent while that of CO_(2) is liner. Explain this on the bases of dipole moment.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a>, <a href="https://interviewquestions.tuteehub.com/tag/polarity-1157527" style="font-weight:bold;" target="_blank" title="Click to know more about POLARITY">POLARITY</a> of molecule = `({:("The vecotr sum "),("of the dipole"),("moments of "),("various bonds"):})` <br/> Shape of `CO_(2) `: the shpae of `CO_(2)` is linear so its become nonpolar. Practically `CO_(2)` is nonpolar. `(mu = 0 )` <br/> Polarity of molecule = Vectro addition of Dipole moment of all bands inmolecule <br/> `CO_(2)` is linear molecule so it is nonpolar experiment `CO_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/non-580180" style="font-weight:bold;" target="_blank" title="Click to know more about NON">NON</a> polar `(mu = 0 ) CO_(2)` is nonpolar it is indirect thus it shape must be like this vector addition of <a href="https://interviewquestions.tuteehub.com/tag/dipolar-2583580" style="font-weight:bold;" target="_blank" title="Click to know more about DIPOLAR">DIPOLAR</a> becomes zero.<br/> In `CO_(2) " two C" <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(rarr)(_)` Obonds are same but if the are in opposite direction than nullify the effect of each other . <br/> `O overset(larr)(_) " C " overset(rarr)(_) O equiv [""^(-delta)O -overset(-2 delta)(C) - O^(-delta) ]^(0)` <br/> `therefore mu = 0 "so , "CO_(2)` is non polar <br/> `H_(2)O : H_(2) O ` is angular `mu` = 1.85 D so it is polar . IN `H_(2) `O .O. is more electronegative than H. <br/> `therefore H - O` bond is polar . `H^(+) o O^(-delta) and H overset(rarr)(_)` son bond has dipole . <br/> The sharp of `H_(2)`O should be like this the net dipole not become zero. <br/> So the arrangement of bond must be angular . Bond angle is `1.4.5^(@) " net " mu = 1.85 D ` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P1_C04_E01_042_S01.png" width="80%"/></body></html>


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