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Although geometries of NH_(3) and H_(2)O molecules are distorted terahedral bond angle in water is less than that of ammonia. Discuss.

Answer» <html><body><p></p>Solution :In `NH_(3)` on N only one lone pair and <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> N - H bonding pair are present so it is `AB_(3)`E type molecule.<br/> In `H_(2)`O one lone pair so due to repulsion it has trigonal pyramidal <a href="https://interviewquestions.tuteehub.com/tag/shape-1204673" style="font-weight:bold;" target="_blank" title="Click to know more about SHAPE">SHAPE</a> and H - N - H bond angle is `<a href="https://interviewquestions.tuteehub.com/tag/107-266703" style="font-weight:bold;" target="_blank" title="Click to know more about 107">107</a>^(@)` while in `H^(2)`O due to repulsion of two lone pair `H_(2)`O has <a href="https://interviewquestions.tuteehub.com/tag/bent-395665" style="font-weight:bold;" target="_blank" title="Click to know more about BENT">BENT</a> shape and bond angle is `10.5^(@)`.<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P1_C04_E01_055_S01.png" width="80%"/></body></html>


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