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Although geometries of NH_3 and H_2O molecules are distorted tetrahedral,bond angle in water is less than that of ammonia.Discuss. |
Answer» <html><body><p></p>Solution :In `NH_3`,there is only one pair on nitrogen atom to repel the <a href="https://interviewquestions.tuteehub.com/tag/bond-900583" style="font-weight:bold;" target="_blank" title="Click to know more about BOND">BOND</a> pairs <a href="https://interviewquestions.tuteehub.com/tag/whereas-2326610" style="font-weight:bold;" target="_blank" title="Click to know more about WHEREAS">WHEREAS</a> in `H_2O`, there are two lone pairs on <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> atom to repel the bond pairs.Hence the repulsion on bond pairs is greater in `H_2O`, than in `NH_3` and so the bond <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> is <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a>.</body></html> | |