1.

Although heat is a path function but heat absorbed by the system under certain specific conditions is independent of path. What are those conditions ? Explain.

Answer» <html><body><p></p>Solution :The two conditions under which heat <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> independent of path are <br/> (i) when volume remains constant <br/> (ii) when pressure remains constant <br/> Explanation <br/> (i) At contant volume. By first <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of thermodynamics, `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> U = <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> + W " or " q = Delta U - W`. But `W = - p Delta V` <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, `q = Delta U + p Delta V`. But as volume remains constant `Delta V = 0` <br/> `:. q_(v) = Delta V " but " Delta U` is a state function. <br/> Hence, `q_(v)` is a state function. <br/> (ii) At constant pressure. As we know, `q_(p) = Delta U + p Delta V`. But `Delta U + p Delta V = Delta H`. <br/> `:. q_(P0 = Delta H`, as `Delta H` is a state function therefore, `q_(p)` is a state function.</body></html>


Discussion

No Comment Found

Related InterviewSolutions