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Aluminimumdissolvesin mineralacids and aqueousalkalies and thus showsamphotericcharacter place ofaluminiumfoil istreatedwith dilutehydrochloricacid or dilutesodium hydroxide solutiona test tube andon bringing a burning matchstick near the monthof thetest tube , a pop southindicatesthe evolutionof hydrogengas. Thesame activitywhenperformedwith concentratednitrogen acid, reaction doesn'tproceed. Explain the reason. |
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Answer» Solution :Al being amphoteric dissolvesboth in acidsand alkalies evolving`H_(2)` gas whichburnswith a popsouth `2Al + 6HCl rarr AlCl_(3) + 3H_(2)` `2Al + 2NaOH + 2H_(2)O rarr underset(" Sod. Meta-aluminate ")(2 NaAlO_(2)) +3H_(2)` With CONC. `HNO_(3)`, Al becomespassive and the reactiondoes not proceed.This passiveis DUE to fromationof a thinpratectivelayer of its oxide `(Al_(2)O_(3))` on the surfaceof themetalwhich preventsfurther ACTION. `2Al + 6HNO_(3) rarr Al_(2)O_(3) + 6NO_(2) + 3H_(2)O`. |
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