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Aluminimumdissolvesin mineralacids and aqueousalkalies and thus showsamphotericcharacter place ofaluminiumfoil istreatedwith dilutehydrochloricacid or dilutesodium hydroxide solutiona test tube andon bringing a burning matchstick near the monthof thetest tube , a pop southindicatesthe evolutionof hydrogengas. Thesame activitywhenperformedwith concentratednitrogen acid, reaction doesn'tproceed. Explain the reason.

Answer» <html><body><p></p>Solution :Al being amphoteric dissolvesboth in acidsand alkalies evolving`H_(2)` gas whichburnswith a popsouth<br/> `2Al + 6HCl rarr AlCl_(3) + 3H_(2)` <br/> `2Al + 2NaOH + 2H_(2)O rarr underset(" Sod. Meta-aluminate ")(2 NaAlO_(2)) +3H_(2)`<br/> With <a href="https://interviewquestions.tuteehub.com/tag/conc-927968" style="font-weight:bold;" target="_blank" title="Click to know more about CONC">CONC</a>. `HNO_(3)`, Al becomespassive and the reactiondoes not proceed.This passiveis <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to fromationof a thinpratectivelayer of its oxide `(Al_(2)O_(3))` on the surfaceof themetalwhich preventsfurther <a href="https://interviewquestions.tuteehub.com/tag/action-2544" style="font-weight:bold;" target="_blank" title="Click to know more about ACTION">ACTION</a>. <br/> `2Al + 6HNO_(3) rarr Al_(2)O_(3) + 6NO_(2) + 3H_(2)O`.</body></html>


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