Aluminium metal forms a cubic close - packed crystal astucture. Its atomic radius is125 xx 10^(-12)m. (a) Calculatethe length of the side of the unit cell. (b) hwo many such unit cells are there in 1.00 m^(3)of aluminium ?

Aluminium metal forms a cubic close - packed crystal astucture. Its at

1.	Aluminium metal forms a cubic close - packed crystal astucture. Its atomic radius is125 xx 10^(-12)m. (a) Calculatethe length of the side of the unit cell. (b) hwo many such unit cells are there in 1.00 m^(3)of aluminium ?
Answer» SOLUTION :ccp = fcc. For fcc, `r = a/(2sqrt(2))or a = 2 sqrt2r = 2 xx 1.414 xx 125 xx 10^(-2) m = 354 xx10^(-12) m =354 "pm"` No. of unit cell in ` 1 m^(3)= 1/(4.436 xx 10^(-29))= 2.25 xx 10^(-29) m^(3)` No. of unit cells in ` 1M ^(3) = 1/( 4.436 xx 10^(-29)) = 2.25 xx 10^(28)`