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Aluminium oxide contains 52.9 % aluminium and carbon dioxide contains 27.27 % carbon. Assuming that the law of Reciprocal proportions is true, calculate the percentage of aluminium in aluminium carbide.

Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/us-718298" style="font-weight:bold;" target="_blank" title="Click to know more about US">US</a> fix `1g` of oxygen with `Al = 52.9 g` <br/> In `Al_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(3),47.1 g` of O are combined with `Al = 52.9 g` <br/> `:. 1.0` g of O is combined with `Al=(52.9)/(47.1)g=1.123g` <br/> In `CO_(2),72.73 g` of O are combined with `C = 27.27 g` <br/> `:.` 1.0 g of O is combined with `C=(27.27)/(72.73)g=0.375g` <br/> The ratio by weight of aluminium and carbon combining with a fixed weight of oxygen in the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> oxides <br/> `1.123 : 0.375` <br/> Since the Law of reciprocal proportions is truem aluminium and carbon in aluminium <a href="https://interviewquestions.tuteehub.com/tag/carbide-413211" style="font-weight:bold;" target="_blank" title="Click to know more about CARBIDE">CARBIDE</a> will combine either in the same ratio or in simple multiple ratio of their weights <br/> `:.` Percentage of `Al` in `Al_(4)C_(3)=(1.123)/(1.123+0.375)xx100=(1.123)/(1.495)xx100=74.97%`.</body></html>


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