Amixture of caustic soda and soda ash requires 25ml 1M HCl for phenolphthalein indicatorand 35ml of 1M HCl for methyl orange indicator. Calculate ratio of (a) number of equivalent and (b) number of moles of the component in the mixture.

Amixture of caustic soda and soda ash requires 25ml 1M HCl for phenolp

1.	Amixture of caustic soda and soda ash requires 25ml 1M HCl for phenolphthalein indicatorand 35ml of 1M HCl for methyl orange indicator. Calculate ratio of (a) number of equivalent and (b) number of moles of the component in the mixture.
Answer» <html><body><p></p>Solution :For phenolphthalein indicator :`NaOH +HCl to NaCl +H_(2)O` <br/> `Na_(2)CO_(3)+HCI to NaCl +NaHCO_(3)` <br/> n=1 for NaOH and n=1 for `Na_(2)CO_(3)` <br/> For methyl orange indicator : `NaOH +HCl to NaCl +H_(2)O`<br/> `Na_(2)CO_(3)+2HClto2NaCl +H_(2)O +CO_(2)` <br/> n=1 for NaOHand n=2 for `Na_(2)CO_(3)` <br/> If x=number of m.eq. of NaOH and y=number of m.eq of `Na_(2)CO_(3)` <br/> `x+y=25 "" x+2y=35` <br/> Solving the values of x and y , y=10, x=15 <br/> (a)Ratio of equivalents of NaOH and`Na_(2)CO_(3)` in the mixture = 15:10=3:2 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Ratio of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of NaOH and `Na_(2)CO(3)` in the mixture =15:5=3:1</body></html>