1.

Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) withcopper ion in alkaline solution but not in acidic solution. This is due to the reason that :

Answer»

in alkaline solution insoluble `Cu(OH)_(2)` is PRECIPITATED which is SOLUBLE in EXCESS of any alkali
`Cu(OH)_(2)` is amphoteric
in acidic solution hydration protects `Cu^(2+)` ion
in acidic solution, proton coordinates with `NH_(3)` forming `NH_(4)^(+)` ion and `NH_(3)` is not available

Solution :It is the correct answer.
`OVERSET(..)(N)H_(3) + underset(("ACID"))(H^(+)) rarr NH_(4)^(+)`
Lone pair is not available for co-ordination with `Cu^(2+)` ion


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