Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) withcopper ion in alkaline solution but not in acidic solution. This is due to the reason that :

Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) withcopper ion in alka

1.	Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) withcopper ion in alkaline solution but not in acidic solution. This is due to the reason that :
Answer» <html><body><p>in alkaline solution insoluble `Cu(OH)_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/precipitated-2948214" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATED">PRECIPITATED</a> which is <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> in <a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a> of any alkali<br/>`Cu(OH)_(2)` is amphoteric<br/>in acidic solution hydration protects `Cu^(2+)` ion<br/>in acidic solution, proton coordinates with `NH_(3)` forming `NH_(4)^(+)` ion and `NH_(3)` is not available </p>Solution :It is the correct answer. <br/>`<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(..)(N)H_(3) + underset(("<a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>"))(H^(+)) rarr NH_(4)^(+)` <br/> Lone pair is not available for co-ordination with `Cu^(2+)` ion</body></html>